Lesson Plan In Mathematics w2p6k

Lesson Plan in Mathematics I-Objectives At the end of the session, Students should be able to: 1. Learn how to Factor Perfect Square Trinomials 2. Solve problems involving Factoring Perfect Square Trinomials 3. Relate Factoring Perfect Square Trinomials to real world application II-Subject Matter Topic – Factoring Perfect Square Trinomials Reference – Grade - 8 Mathematics Module Materials – Algebra tiles, Visual aids III-Development of the lesson A. Preliminaries 1. Prayer 2. Greetings 3. Roll call B. Recall Review on Squaring Binomials C. Motivation ‘Group Activity’ How to play the game? a. Teacher will group the class into two. b. Students will compete to form squares using algebra tiles. Form squares using:  1 big square tile, 4 rectangular tiles, and 4 small square tiles  4 big square tiles, 4 rectangular tiles, and 1 small square tile  4 big square tiles, 8 rectangular tiles, and 4 small square tiles c. Winner will receive the wow clap d. Introduction of Algebra tiles Algebra Tiles  Manipulatives used to represent polynomials and perform polynomials operations  Consists of large squares (x2-tiles), rectangles (x-tiles), and small squres (1-tiles)

x2 tile

x tile

-x2 tile

1 tile

-x tile

-1 tile

D. Discussion A Perfect Square Trinomials is the result of squaring a binomial. It has first and last which are perfect squares and a middle term which is twice the product of the square root of the first and last term. Study the relationship, (

a ±

first term

b )2 second term

=

a2 ± 2ab

first term

+

middle term

b2 last term

1. How can we factor perfect Square Trinomials? 2. Guide the students to discover the steps in factoring perfect square trinomials. To factor Perfect Square Trinomials; a. Get the square root of the first and last . b. List down the square root as sum/difference as the case may be. 3. Let the students observe the examples #1. Factor n2 + 16n + 64

Solution 2 a. √ n = n

√ 64 = 8 b. n2 + 16n + 64 = (n + 8) (n + 8) or (n + 8)2 #2. Factor 4r2 – 12r + 9 Solution √ 4 r 2 = 2r a.

√9 = 3 b. 4r2 – 12r + 9 = (2r – 3) (2r – 3) or (2r – 3)2 #3. The boxing ring has an area of (25x2 – 20x + 4) m2. The side length of the boxing ring is in the form of cx – d, where c and d are whole numbers. What is the length of its side? Given. 25x2 – 20x + 4 square meters – Area of the boxing ring Problem. What is the length of the side of the ring? Solution: a.

√ 25 x 2

= 5x

√4 = 2 b. 25x2 – 20x + 4 = (5x-2) (5x-2) or (5x-2)2 Area = (side)2 Side = √ Area 2 5 x−¿ ¿ c. Side = ¿ √¿ Side = (5x-2) Answer. The boxing ring has a side of (5x-2). Checking. Using the FOIL method (5x-2)2 or (5x-2)(5x-2) (5x) (5x) = 25x2 (5x) (-2) = -10x (-2)(5x) = -10x (-2)(-2) = 4 25x2-10x-10x + 4 (5x-2)2= 25x2-20x + 4 IV – Evaluation Find the factors of the following expressions. 1. x2 + 2x +1 2. a2 + 2ab + b2 3. 16x2 – 24x + 9 4-5. solve. (2 pts.) The rice field is in the square shape and covers a total area of (4b2 – 4b + 1) km2; Find the length of its side. The side length is in the form xb – y, where x and y are whole numbers. V- Assignment

List down 20 perfect square trinomials. Prepared by, Joel M. Lupango