Pr Pondim 2 Farhan 1w2r70
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problem set 2 (2)
NAME: Student ID: MODULE HW2 DF
Ryamizard Farhan Hermawan 0311 16 40000 0 4
e
100 Pz=
7th ed Feb 2019 0.3
4.78 ton m eccentricity of Pz and machine, e =
0.3 m Z
0.3 machine weight m 1.764 ton
0.25 m L =zo=
0.35 m 0.3 m
8
0.53940
0.25 m
0.6 m
0.9 m
machine elev. +1,25
0.3 m X
2.3
m
A m
O a=
h
0.3
0
2.10 meter
m
0
±0,00
Y xo=
#N/A m
0 m 2.10 m
yo = #N/A m 1.7 m st = A= Cu = Ct = Cf = C'u = C't = C'f = w= m= Pz = My = I= Wtotal= zo= L=
2.0500 4.8300 3550.0000 1775.0000 7100.0000 5108.0459 2554.0229 10216.0917 10.4667 1.0912 4.7800 1.4340 2.1292 10.9116 0.5394
m
10 m/dt2
kg/cm m2 note: fill in with 4 decimal 3 ton/m Amplitude with 8 decimal 3 ton/m ton/m3 ton/m3 with correction 3 ton/m with correction 3 ton/m with correction --machine operating frequency rad/dt 1.667 s f= 100 rpm 2 ton dt /m rz= 0.0696 ton freq ratio TR= 1.0049 ton m Transmissibility 4 m s static = W total ton M .c ± A m 0.2259 + I 0.0000 kg/cm2 2
0.8030 ton m dt2
Mm=
0.4855 ton m dt =Mmo-m.z s st+dy= 0.6046 0.6106 m
h=
2.1
0 m X gravity acceleration, g =
Mmo= g =
b=
2
=
0.2259
kg/cm2
2 o
W total +P z T R
A
0.3254 + =
Page 1
±
(M + Pz T R . e ) c 0.1064 0.4318
I
kg/cm2 kg/cm2
problem set 2 (2)
NAME: Student ID:
Ryamizard Farhan Hermawan 31 16 40000 0 4
MODULE HW2 DF 7th ed Feb 2019 Vertical: wnz = 150.3685 rad/dt Az = 0.19468722 Lateral wnx = 106.3266 rad/dt Rocking: wnf = 164.564885 rad/dt assume couple mode (wn1)2 = 54139.0092 (wn2)2 = 232.6779 wn1 = 232.6779 rad/dt wn2 =
8
mm fnx=
16.922397 s =
1015.3438 rpm
fnf=
26.191315 s =
1571.4789 rpm
Uncouple mode is OK if
√( f
2 +f 2 nφ nx
)
2 f nx f nφ <3 . f mesin0.00667 OK 0.00117
15.2538 rad/dt
¿
coupled mode not necessary
r = 544.7180 mm D(w ) = 264580893.2760 center of rotating : Ax = 0.0000361 m 0.5447 m 0.0361 mm at machine elevation Horizontal and Rocking Af = 0.0000662 radial assume uncouple mode 2
AH=
= Ax + h x Af 0.0764924 mm Ax+hAf=AH at machine elevation (centroid)
AH=
0.0761413
Af =
0.00006621
mm radial
h r
Total vertical amplitude at A Az= A
Af.a/2 = Av=
0.1946872
+
0.0761425
mm mm +
mm= inch Psychological effects on persons TROUBLESOME to Persons (check with graph no. 3.1) Getaran Horizontal: Getaran Vertikal: Nilai K menurut Dieckman : 0.4250 Nilai K menurut Dieckman : 0.7523 Check with table 3-3 and table 3-4 for Criteria V horizontal: 0.0315 inch/sec PPV vertical: 0.1117 inch/sec a/2=
1.15 m
Very Good check with table 3-2
0.2708297 0.0106626
check with graph 3.2 , graph 3.3 and table 10-6
Page 2
problem set 2 (2)
Page 3
problem set 2 (2)
Page 4
problem set 2 (2)
Page 5
problem set 2 (2)
Page 6
problem set 2 (2)
Page 7
problem set 2 (2)
Page 8
problem set 2 (2)
Page 9
problem set 2 (2)
Page 10
problem set 2 (2)
√
Page 11
(
x n
)
(
± 0,00
)
problem set 2 (2)
achine elev.
±0,00
Page 12
problem set 2 (2)
TROUBLESO
Page 13
problem set 2 (2)
± 0,00
Page 14
problem set 2
NAME: Student ID: MODULE HW2 DF
0311
shalva 40000
16
0
5
e
100 Pz=
7th ed Feb 2019 0.4
3.1 ton m eccentricity of Pz and machine, e =
0.3 m Z
0.3 machine weight m 0.765 ton
0.35 m L =zo=
0.25 m 0.3 m
4
0.60000
0.25 m
0.6 m
0.9 m
machine elev. +1,25
0.3 m X
2.3
m
A m
O a=
h
0.4
0
1.70 meter
m
0
±0,00
Y xo=
1.1500 m
0 m 1.70 m
yo = 0.8500 m 1.7 m st =
zo= L=
2.6500 3.9100 4150.0000 2075.0000 8300.0000 6636.8151 3318.4075 13273.6302 9.4200 8.1074 3.1000 1.2400 1.7237 11.1740 0.6000
Mmo=
1.7237
A= Cu = Ct = Cf = C'u = C't = C'f = w= m= Pz = My = I= Wtotal=
Mm= g = h=
b=
1.7
m
0 m X gravity acceleration, g =
10 m/dt2
kg/cm m2 note: fill in with 4 decimal 3 ton/m Amplitude with 8 decimal 3 ton/m ton/m3 ton/m3 with correction 3 ton/m with correction 3 ton/m with correction --machine operating frequency rad/dt 1.500 s f= 90 rpm 2 ton dt /m rz= ton 0.2000 freq ratio T = ton m 2.0000 Transmissibility R m4 W total M .c ± s static = ton A I m 2.0000 + 3100.0000 kg/cm2 2
ton m dt2
=
ton m dt =Mmo-m.z 2.0000 s st+dy= 2400.0000 2.0000 m 2
2 o
W total +P z T R
A 2.0000 + =
Page 15
2.0000
±
kg/cm2
(M + Pz T R . e ) c I 2.0000 2.0000
kg/cm2 kg/cm2
problem set 2
NAME: Student ID:
31
shalva 40000
16
0
5
4
MODULE HW2 DF 7th ed Feb 2019 Vertical: wnz =
3.0000 rad/dt Az = 2.89000000 Lateral wnx = 179.9087 rad/dt Rocking: wnf = 3.0000 rad/dt assume couple mode (wn1)2 = 3.0000 (wn2)2 = 3.0000 wn1 = 1.7321 rad/dt wn2 =
mm fnx=
28.633359 s =
1718.0015 rpm
fnf=
0.4774648 s =
28.64789 rpm
Uncouple mode is OK if
√( f
2 +f 2 nφ nx
f nx f nφ
1.7321 rad/dt
)
¿
2 3 . f mesin
3.0000 > 3.0000 NO coupled modes should be considered
D(w2) = 294109759.6880 Ax = 3.00000000 m
center of rotating :
3.00000000 radial
AH=
= Ax + h x Af 3.00000000 mm Ax+hAf=AH at machine elevation (centroid)
3.0000
mm
0.0030 m Horizontal and Rocking
3.00000000 mm at machine elevation Af =
r =
assume uncouple mode AH= 3.00000000
mm
Af =
radial
3.00000000
h r
Total vertical amplitude at A Az= A
Af.a/2 =
+
2.8900000
mm
3.00000000
mm +
Av=
3.00000000 mm= 3.00000000 inch Psychological effects on persons TROUBLESOME to Persons (check with graph no. 3.1) Getaran Horizontal: Getaran Vertikal: Nilai K menurut Dieckman : 3.0000 Nilai K menurut Dieckman : 3.0000 Check with table 3-3 and table 3-4 for Criteria V horizontal: 3.0000 inch/sec PPV vertical: 3.0000 inch/sec a/2=
1.15 m
Fair to Rough check with table 3-2
check with graph 3.2 , graph 3.3 and table 10-6
Page 16
problem set 2
Page 17
problem set 2
Page 18
problem set 2
Page 19
problem set 2
Page 20
problem set 2
Page 21
problem set 2
Page 22
problem set 2
Page 23
problem set 2
Page 24
problem set 2
√
Page 25
(
n
x
)
(
)
± 0,00
problem set 2
achine elev.
±0,00
Page 26
problem set 2
TROUBLESO
Page 27
problem set 2
± 0,00
Page 28
Compatibility Report for MODULpr2DFOct2014.xls Run on 10/5/2014 9:50 The following features in this workbook are not ed by earlier versions of Excel. These features may be lost or degraded when you save this workbook in an earlier file format. Minor loss of fidelity Some cells or styles in this workbook contain formatting that is not ed by the selected file format. These formats will be converted to the closest format available.
# of occurrences 44
NAME: Student ID: MODULE HW2 DF
Ryamizard Farhan Hermawan 0311 16 40000 0 4
e
100 Pz=
7th ed Feb 2019 0.3
4.78 ton m eccentricity of Pz and machine, e =
0.3 m Z
0.3 machine weight m 1.764 ton
0.25 m L =zo=
0.35 m 0.3 m
8
0.53940
0.25 m
0.6 m
0.9 m
machine elev. +1,25
0.3 m X
2.3
m
A m
O a=
h
0.3
0
2.10 meter
m
0
±0,00
Y xo=
#N/A m
0 m 2.10 m
yo = #N/A m 1.7 m st = A= Cu = Ct = Cf = C'u = C't = C'f = w= m= Pz = My = I= Wtotal= zo= L=
2.0500 4.8300 3550.0000 1775.0000 7100.0000 5108.0459 2554.0229 10216.0917 10.4667 1.0912 4.7800 1.4340 2.1292 10.9116 0.5394
m
10 m/dt2
kg/cm m2 note: fill in with 4 decimal 3 ton/m Amplitude with 8 decimal 3 ton/m ton/m3 ton/m3 with correction 3 ton/m with correction 3 ton/m with correction --machine operating frequency rad/dt 1.667 s f= 100 rpm 2 ton dt /m rz= 0.0696 ton freq ratio TR= 1.0049 ton m Transmissibility 4 m s static = W total ton M .c ± A m 0.2259 + I 0.0000 kg/cm2 2
0.8030 ton m dt2
Mm=
0.4855 ton m dt =Mmo-m.z s st+dy= 0.6046 0.6106 m
h=
2.1
0 m X gravity acceleration, g =
Mmo= g =
b=
2
=
0.2259
kg/cm2
2 o
W total +P z T R
A
0.3254 + =
Page 1
±
(M + Pz T R . e ) c 0.1064 0.4318
I
kg/cm2 kg/cm2
problem set 2 (2)
NAME: Student ID:
Ryamizard Farhan Hermawan 31 16 40000 0 4
MODULE HW2 DF 7th ed Feb 2019 Vertical: wnz = 150.3685 rad/dt Az = 0.19468722 Lateral wnx = 106.3266 rad/dt Rocking: wnf = 164.564885 rad/dt assume couple mode (wn1)2 = 54139.0092 (wn2)2 = 232.6779 wn1 = 232.6779 rad/dt wn2 =
8
mm fnx=
16.922397 s =
1015.3438 rpm
fnf=
26.191315 s =
1571.4789 rpm
Uncouple mode is OK if
√( f
2 +f 2 nφ nx
)
2 f nx f nφ <3 . f mesin0.00667 OK 0.00117
15.2538 rad/dt
¿
coupled mode not necessary
r = 544.7180 mm D(w ) = 264580893.2760 center of rotating : Ax = 0.0000361 m 0.5447 m 0.0361 mm at machine elevation Horizontal and Rocking Af = 0.0000662 radial assume uncouple mode 2
AH=
= Ax + h x Af 0.0764924 mm Ax+hAf=AH at machine elevation (centroid)
AH=
0.0761413
Af =
0.00006621
mm radial
h r
Total vertical amplitude at A Az= A
Af.a/2 = Av=
0.1946872
+
0.0761425
mm mm +
mm= inch Psychological effects on persons TROUBLESOME to Persons (check with graph no. 3.1) Getaran Horizontal: Getaran Vertikal: Nilai K menurut Dieckman : 0.4250 Nilai K menurut Dieckman : 0.7523 Check with table 3-3 and table 3-4 for Criteria V horizontal: 0.0315 inch/sec PPV vertical: 0.1117 inch/sec a/2=
1.15 m
Very Good check with table 3-2
0.2708297 0.0106626
check with graph 3.2 , graph 3.3 and table 10-6
Page 2
problem set 2 (2)
Page 3
problem set 2 (2)
Page 4
problem set 2 (2)
Page 5
problem set 2 (2)
Page 6
problem set 2 (2)
Page 7
problem set 2 (2)
Page 8
problem set 2 (2)
Page 9
problem set 2 (2)
Page 10
problem set 2 (2)
√
Page 11
(
x n
)
(
± 0,00
)
problem set 2 (2)
achine elev.
±0,00
Page 12
problem set 2 (2)
TROUBLESO
Page 13
problem set 2 (2)
± 0,00
Page 14
problem set 2
NAME: Student ID: MODULE HW2 DF
0311
shalva 40000
16
0
5
e
100 Pz=
7th ed Feb 2019 0.4
3.1 ton m eccentricity of Pz and machine, e =
0.3 m Z
0.3 machine weight m 0.765 ton
0.35 m L =zo=
0.25 m 0.3 m
4
0.60000
0.25 m
0.6 m
0.9 m
machine elev. +1,25
0.3 m X
2.3
m
A m
O a=
h
0.4
0
1.70 meter
m
0
±0,00
Y xo=
1.1500 m
0 m 1.70 m
yo = 0.8500 m 1.7 m st =
zo= L=
2.6500 3.9100 4150.0000 2075.0000 8300.0000 6636.8151 3318.4075 13273.6302 9.4200 8.1074 3.1000 1.2400 1.7237 11.1740 0.6000
Mmo=
1.7237
A= Cu = Ct = Cf = C'u = C't = C'f = w= m= Pz = My = I= Wtotal=
Mm= g = h=
b=
1.7
m
0 m X gravity acceleration, g =
10 m/dt2
kg/cm m2 note: fill in with 4 decimal 3 ton/m Amplitude with 8 decimal 3 ton/m ton/m3 ton/m3 with correction 3 ton/m with correction 3 ton/m with correction --machine operating frequency rad/dt 1.500 s f= 90 rpm 2 ton dt /m rz= ton 0.2000 freq ratio T = ton m 2.0000 Transmissibility R m4 W total M .c ± s static = ton A I m 2.0000 + 3100.0000 kg/cm2 2
ton m dt2
=
ton m dt =Mmo-m.z 2.0000 s st+dy= 2400.0000 2.0000 m 2
2 o
W total +P z T R
A 2.0000 + =
Page 15
2.0000
±
kg/cm2
(M + Pz T R . e ) c I 2.0000 2.0000
kg/cm2 kg/cm2
problem set 2
NAME: Student ID:
31
shalva 40000
16
0
5
4
MODULE HW2 DF 7th ed Feb 2019 Vertical: wnz =
3.0000 rad/dt Az = 2.89000000 Lateral wnx = 179.9087 rad/dt Rocking: wnf = 3.0000 rad/dt assume couple mode (wn1)2 = 3.0000 (wn2)2 = 3.0000 wn1 = 1.7321 rad/dt wn2 =
mm fnx=
28.633359 s =
1718.0015 rpm
fnf=
0.4774648 s =
28.64789 rpm
Uncouple mode is OK if
√( f
2 +f 2 nφ nx
f nx f nφ
1.7321 rad/dt
)
¿
2 3 . f mesin
3.0000 > 3.0000 NO coupled modes should be considered
D(w2) = 294109759.6880 Ax = 3.00000000 m
center of rotating :
3.00000000 radial
AH=
= Ax + h x Af 3.00000000 mm Ax+hAf=AH at machine elevation (centroid)
3.0000
mm
0.0030 m Horizontal and Rocking
3.00000000 mm at machine elevation Af =
r =
assume uncouple mode AH= 3.00000000
mm
Af =
radial
3.00000000
h r
Total vertical amplitude at A Az= A
Af.a/2 =
+
2.8900000
mm
3.00000000
mm +
Av=
3.00000000 mm= 3.00000000 inch Psychological effects on persons TROUBLESOME to Persons (check with graph no. 3.1) Getaran Horizontal: Getaran Vertikal: Nilai K menurut Dieckman : 3.0000 Nilai K menurut Dieckman : 3.0000 Check with table 3-3 and table 3-4 for Criteria V horizontal: 3.0000 inch/sec PPV vertical: 3.0000 inch/sec a/2=
1.15 m
Fair to Rough check with table 3-2
check with graph 3.2 , graph 3.3 and table 10-6
Page 16
problem set 2
Page 17
problem set 2
Page 18
problem set 2
Page 19
problem set 2
Page 20
problem set 2
Page 21
problem set 2
Page 22
problem set 2
Page 23
problem set 2
Page 24
problem set 2
√
Page 25
(
n
x
)
(
)
± 0,00
problem set 2
achine elev.
±0,00
Page 26
problem set 2
TROUBLESO
Page 27
problem set 2
± 0,00
Page 28
Compatibility Report for MODULpr2DFOct2014.xls Run on 10/5/2014 9:50 The following features in this workbook are not ed by earlier versions of Excel. These features may be lost or degraded when you save this workbook in an earlier file format. Minor loss of fidelity Some cells or styles in this workbook contain formatting that is not ed by the selected file format. These formats will be converted to the closest format available.
# of occurrences 44
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