problem set 2 (2)
NAME: Student ID: MODULE HW2 DF
Ryamizard Farhan Hermawan 0311 16 40000 0 4
e
100 Pz=
7th ed Feb 2019 0.3
4.78 ton m eccentricity of Pz and machine, e =
0.3 m Z
0.3 machine weight m 1.764 ton
0.25 m L =zo=
0.35 m 0.3 m
8
0.53940
0.25 m
0.6 m
0.9 m
machine elev. +1,25
0.3 m X
2.3
m
A m
O a=
h
0.3
0
2.10 meter
m
0
±0,00
Y xo=
#N/A m
0 m 2.10 m
yo = #N/A m 1.7 m st = A= Cu = Ct = Cf = C'u = C't = C'f = w= m= Pz = My = I= Wtotal= zo= L=
2.0500 4.8300 3550.0000 1775.0000 7100.0000 5108.0459 2554.0229 10216.0917 10.4667 1.0912 4.7800 1.4340 2.1292 10.9116 0.5394
m
10 m/dt2
kg/cm m2 note: fill in with 4 decimal 3 ton/m Amplitude with 8 decimal 3 ton/m ton/m3 ton/m3 with correction 3 ton/m with correction 3 ton/m with correction --machine operating frequency rad/dt 1.667 s f= 100 rpm 2 ton dt /m rz= 0.0696 ton freq ratio TR= 1.0049 ton m Transmissibility 4 m s static = W total ton M .c ± A m 0.2259 + I 0.0000 kg/cm2 2
0.8030 ton m dt2
Mm=
0.4855 ton m dt =Mmo-m.z s st+dy= 0.6046 0.6106 m
h=
2.1
0 m X gravity acceleration, g =
Mmo= g =
b=
2
=
0.2259
kg/cm2
2 o
W total +P z T R
A
0.3254 + =
Page 1
±
(M + Pz T R . e ) c 0.1064 0.4318
I
kg/cm2 kg/cm2
problem set 2 (2)
NAME: Student ID:
Ryamizard Farhan Hermawan 31 16 40000 0 4
MODULE HW2 DF 7th ed Feb 2019 Vertical: wnz = 150.3685 rad/dt Az = 0.19468722 Lateral wnx = 106.3266 rad/dt Rocking: wnf = 164.564885 rad/dt assume couple mode (wn1)2 = 54139.0092 (wn2)2 = 232.6779 wn1 = 232.6779 rad/dt wn2 =
8
mm fnx=
16.922397 s =
1015.3438 rpm
fnf=
26.191315 s =
1571.4789 rpm
Uncouple mode is OK if
√( f
2 +f 2 nφ nx
)
2 f nx f nφ <3 . f mesin0.00667 OK 0.00117
15.2538 rad/dt
¿
coupled mode not necessary
r = 544.7180 mm D(w ) = 264580893.2760 center of rotating : Ax = 0.0000361 m 0.5447 m 0.0361 mm at machine elevation Horizontal and Rocking Af = 0.0000662 radial assume uncouple mode 2
AH=
= Ax + h x Af 0.0764924 mm Ax+hAf=AH at machine elevation (centroid)
AH=
0.0761413
Af =
0.00006621
mm radial
h r
Total vertical amplitude at A Az= A
Af.a/2 = Av=
0.1946872
+
0.0761425
mm mm +
mm= inch Psychological effects on persons TROUBLESOME to Persons (check with graph no. 3.1) Getaran Horizontal: Getaran Vertikal: Nilai K menurut Dieckman : 0.4250 Nilai K menurut Dieckman : 0.7523 Check with table 3-3 and table 3-4 for Criteria V horizontal: 0.0315 inch/sec PPV vertical: 0.1117 inch/sec a/2=
1.15 m
Very Good check with table 3-2
0.2708297 0.0106626
check with graph 3.2 , graph 3.3 and table 10-6
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problem set 2 (2)
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problem set 2 (2)
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problem set 2 (2)
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problem set 2 (2)
√
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(
x n
)
(
± 0,00
)
problem set 2 (2)
achine elev.
±0,00
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problem set 2 (2)
TROUBLESO
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problem set 2 (2)
± 0,00
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problem set 2
NAME: Student ID: MODULE HW2 DF
0311
shalva 40000
16
0
5
e
100 Pz=
7th ed Feb 2019 0.4
3.1 ton m eccentricity of Pz and machine, e =
0.3 m Z
0.3 machine weight m 0.765 ton
0.35 m L =zo=
0.25 m 0.3 m
4
0.60000
0.25 m
0.6 m
0.9 m
machine elev. +1,25
0.3 m X
2.3
m
A m
O a=
h
0.4
0
1.70 meter
m
0
±0,00
Y xo=
1.1500 m
0 m 1.70 m
yo = 0.8500 m 1.7 m st =
zo= L=
2.6500 3.9100 4150.0000 2075.0000 8300.0000 6636.8151 3318.4075 13273.6302 9.4200 8.1074 3.1000 1.2400 1.7237 11.1740 0.6000
Mmo=
1.7237
A= Cu = Ct = Cf = C'u = C't = C'f = w= m= Pz = My = I= Wtotal=
Mm= g = h=
b=
1.7
m
0 m X gravity acceleration, g =
10 m/dt2
kg/cm m2 note: fill in with 4 decimal 3 ton/m Amplitude with 8 decimal 3 ton/m ton/m3 ton/m3 with correction 3 ton/m with correction 3 ton/m with correction --machine operating frequency rad/dt 1.500 s f= 90 rpm 2 ton dt /m rz= ton 0.2000 freq ratio T = ton m 2.0000 Transmissibility R m4 W total M .c ± s static = ton A I m 2.0000 + 3100.0000 kg/cm2 2
ton m dt2
=
ton m dt =Mmo-m.z 2.0000 s st+dy= 2400.0000 2.0000 m 2
2 o
W total +P z T R
A 2.0000 + =
Page 15
2.0000
±
kg/cm2
(M + Pz T R . e ) c I 2.0000 2.0000
kg/cm2 kg/cm2
problem set 2
NAME: Student ID:
31
shalva 40000
16
0
5
4
MODULE HW2 DF 7th ed Feb 2019 Vertical: wnz =
3.0000 rad/dt Az = 2.89000000 Lateral wnx = 179.9087 rad/dt Rocking: wnf = 3.0000 rad/dt assume couple mode (wn1)2 = 3.0000 (wn2)2 = 3.0000 wn1 = 1.7321 rad/dt wn2 =
mm fnx=
28.633359 s =
1718.0015 rpm
fnf=
0.4774648 s =
28.64789 rpm
Uncouple mode is OK if
√( f
2 +f 2 nφ nx
f nx f nφ
1.7321 rad/dt
)
¿
2 3 . f mesin
3.0000 > 3.0000 NO coupled modes should be considered
D(w2) = 294109759.6880 Ax = 3.00000000 m
center of rotating :
3.00000000 radial
AH=
= Ax + h x Af 3.00000000 mm Ax+hAf=AH at machine elevation (centroid)
3.0000
mm
0.0030 m Horizontal and Rocking
3.00000000 mm at machine elevation Af =
r =
assume uncouple mode AH= 3.00000000
mm
Af =
radial
3.00000000
h r
Total vertical amplitude at A Az= A
Af.a/2 =
+
2.8900000
mm
3.00000000
mm +
Av=
3.00000000 mm= 3.00000000 inch Psychological effects on persons TROUBLESOME to Persons (check with graph no. 3.1) Getaran Horizontal: Getaran Vertikal: Nilai K menurut Dieckman : 3.0000 Nilai K menurut Dieckman : 3.0000 Check with table 3-3 and table 3-4 for Criteria V horizontal: 3.0000 inch/sec PPV vertical: 3.0000 inch/sec a/2=
1.15 m
Fair to Rough check with table 3-2
check with graph 3.2 , graph 3.3 and table 10-6
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problem set 2
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problem set 2
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problem set 2
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problem set 2
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problem set 2
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problem set 2
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problem set 2
√
Page 25
(
n
x
)
(
)
± 0,00
problem set 2
achine elev.
±0,00
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problem set 2
TROUBLESO
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problem set 2
± 0,00
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# of occurrences 44