1 DESIGN OF MAIN BEAM Design wind load 0.16 kN/m^2 [As per IS 800- 2007] Analysis: DL = WL thr =
2
0.05 kN/m 2 0.16 kN/m
Purlin spacing = Main beam spacing= Loading on main beam: DL = 0.05 x 4 = WLthr = 0.16 x 4 =
-Thrust pressure (downwards)
1.2 m 4m 0.2 kN/m 0.64 kN/m
-UDL on main beam due to DL -UDL on main beam due to Thrust pressure
*Considering the loads acting on main beam as UDL instead of point loads that are transferred from purlin to main beam. Load Combinations for design: (As per IS 800-2007) 1.5 (DL+WLthr) = 1.40601 kN/m
-Acting downwards
UDL 1.2 m 8m Rf
Re Loading on the main beam and condition Spacing of purlins = No. of purlins =
1.2 m 7
-From the symmetry of the loading, the reaction force from beam are; Re = R f = -For the load case 1.5 (DL+WLthr), downwards 5.62404 kN
Bending Moment: Mmax = 11.248 kN-m
-For the load case 1.5 (DL+WLthr), downwards (Maxm. BM at section of the beam)
1
bf = 80
Trial Section:
tf = 4 BUILT UP SECTION (refer fig.) Grade: E 350 fu= 490 MPa fy=
dw = 150
350 MPa
tw = 4
tf, tw- thickness of flange & web respectively dw- clear depth of the web bf- width of the flange *All dimensions are in mm Sectional properties: A= H= rz=
1240 mm 158 63.0 mm
Zze=
2
3
3
3
3
Zzp=
9.73 kg/m
ry=
16.6 mm 8.6 x103 mm3 0.3421 x106 mm4
Zye=
62.3 x10 mm 4.92 x106 mm4
Iz=
m=
Iy=
Zyp= 71.780 x10 mm Y_ver= 57.887 X_hori= mm Zze,Zye- Elastic section modulus @ major & minor axes respectively
13.40 x103 mm3 10.8065 mm
Zzp,Zyp- Plastic section modulus @ major & minor axes respectively Iz,Iy- Second moment of area @ major & minor axes respectively rz,ry- Radius of gyration @ major & minor axes respectively D,t- Depth & thickness of the section respectively m- mass per unit length of the section Classification of section =√(250/ _ )
For I-sections: Plastic Compact 9.4ε 10.5ε 7.944 8.874 b/tf= 9.500
=
0.8452
Semi-compact 15.7ε 13.269
[ As per Table 2 of IS 800- 2007] b- outstand element of compression flange tf- thickness of the flange
.'. Section is
Semi-compact
2
βb =
0.868
Moment carrying capacity of the section Md- moment carrying capacity of the section
_ = _
_
_
zp- plastic section modulus for the given c/s fbd- design bending compressive stress
Calculation of fbd: _
/
_
=
72.243
h= tf =
154.0 mm 4 mm
h/tf =
h- c/c distace betwn. the flanges
38.50
fcr,b interpolation h/t LLT/r
35 38.5 70 485.5 478.85 72.243 455.4736 80 381.2 374.62 .'. fcr,b = 455.4736004
40 476 371.8 -Table 14 of IS 800- 2007
αLT= 0.49
-For Builtup steel sections
fbd interpolation fy .'. fcr,b 500 455.4736 450 .'. fbd =
350 203.55 195.0455 191.6 194 195.045 MPa
.'. Md =
340 200.9
360 206.2 196.4 -Table 13 (b) of IS 800- 2007
12.148 kN-m
-Moment carrying capacity of the section
Md >
SAFE
Mmax.
Stress Ratio=
0.926
where, M max. is maxm. bending moment in the main beam for the all possible load cases. Shear capacity of the section: Vu,max = 5.62404 kN
-For the load case 1.5 (DL+WL thr), downwards -Maxm. SF at section of the beam
_ =( _ × _ )/(ϒ_ ×√3)
Vd - shear capacity of the section fyw - yield strength of web of the section ϒmo - partial safety factor= 1.1 3
Av -Shear area of the section i.e web area for I-sectn. 2
Av =
600 mm
fyw=
350 MPa .'. Vd=
110.221 kN
0.6 Vd=
66.13 kN
.'. 0.6 Vd >
Vu,max
Hence SAFE
[As per Cl. 8.2.1.2 of IS 800- 2007]
Deflection: Load Combinations for serviceability: 1.0 (DL+WLthr) = 0.937 kN/m Δ_ =(5 _ ^4)/384 Δ_ = Δ_ =
-Acting downwards
-Maxm. deflection at any point in the beam for any possible load case (occuring at the mid-point of the beam)
50.800 mm span/150 =
-So, no reduction in moment carrying capacity is to be made
53.33 mm
Hence OK
4